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Light of wavelength 5000 Å falls on a se...

Light of wavelength `5000 Å` falls on a sensitive plate with photoelectric work function of `1.9 eV`. The kinetic energy of the photoelectron emitted will be

A

0.58 eV

B

2.48 eV

C

1.24 eV

D

1.16 eV

Text Solution

Verified by Experts

The correct Answer is:
A
`K_("max") = (hc)/lamda -phi_0`
`= (12375)/(5000)(eV) -1.9 eV = 0.57 eV ~~0.58eV`
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