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If the energy of a photon corresponding ...

If the energy of a photon corresponding to a wavelength of `6000 Å is 3.32 xx 10^(-19) J` , the photon energy for a wavelength of `4000 Å` will be

A

`1.4 eV`

B

`4.9 eV`

C

`3.1 eV`

D

`1.6 eV`

Text Solution

Verified by Experts

The correct Answer is:
C
Since, `E = (hc)/lamda implies E_1/E_2 = lamda_2/lamda_1`
`implies E_2 = (6000)/(4000) xx3.32 xx10^(-19) =3.1eV`
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