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In an experiment of photoelectric effect...

In an experiment of photoelectric effect the stopping potential was measured to be `V_(1)` and `V_(2)` with incident light of wavelength `lambda` and `(lambda)/(2)`, respectively. The relation between `V_(1)` and `V_(2)` is:

A

`V_2 lt V_1`

B

`V_1 lt V_2 lt 2V_1`

C

`V_2 =2V_1`

D

`V_2 gt 2V_1`

Text Solution

Verified by Experts

The correct Answer is:
D
`eV_0=(hc)/lamda -phi_0`
`impliesV_0=(hc)/(elamda)-phi_0/e`
`:. V_1 =(hc)/(lamdae) -phi_0/e`
and `V_2=(hc)/((lamda/2)e)-phi_0/e`
`V_2=(2hc)/(lamdae)-phi_0/e =(2hc)/(lamdae)-(2phi_0)/e +(2phi_0)/e-(2phi_0)/e`
`V_2 =2V_1 +(phi_0)/e`
`:. V_2 gt 2V_1`
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