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A photon of wavelength 300nm interacts w...

A photon of wavelength 300nm interacts with a stationary hydrogen atom in ground state. During the interaction, whole energy of the photon is transferred to the electron of the atom. State which possibility is correct, (consider, Plank's constant `=4xx10^(-15)` eVs, velocity of light `=3xx10^(8)ms^(-1)` ionization energy of hydrogen =13.6 eV)

A

Electron will be knocked out of the atom

B

Electron will go to any excited state of the atom

C

Electron will go only to first excited state of the atom

D

Electron will keep orbiting in the ground state of atom

Text Solution

Verified by Experts

The correct Answer is:
D
`E_("ph) = (hc)/lamda(eV) = (4 xx10^(-15)xx3xx10^8)/(300 xx10^(-9))=4eV`
`1^(st)` excitation energy = 10.2eV for an electron
Since, `E_(ph) lt ` 10.2eV, no excitation in possible.
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