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A photon of wavelength lamda is absorbe...

A photon of wavelength `lamda` is absorbed by an electron confined to a box of length `sqrt(35hlamda//8mc)` . As a result, the electron makes a transition from state k = 1 to the state n Subsequently the electron transits from the state n to the state m by emitting a photon of wavelength `lamda = 1.75lamda` then

A

`n = 4 :m = 2`

B

`n = 5 :m = 3`

C

`n = 6 :m = 4`

D

`n = 3 :m = 1`

Text Solution

Verified by Experts

The correct Answer is:
C
KE of `e^(-) = (hc)/lamda`

`lamda_("de - Broglie") =h/(sqrt(2mKE))=h/(sqrt(2mxx(hc)/lamda))=(sqrt(hlamda))/(sqrt(2mc))`
`(m_0lamda_("de-Broglie"))/2=l`
`impliesm_0/2xxsqrt((hlamda)/(2mc))=sqrt(35hlamda)/(sqrt(8mc))implies m_0=sqrt35=5.8 ~~6`
i.e. `e^(-)` get excite to state 6, `:. n = 6`
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