Home
Class 12
PHYSICS
An alpha particle and a proton are accel...

An alpha particle and a proton are accelerated from rest by a potential difference of 200 V. After this, their de Broglie wavelengths are `lambda_(alpha)` and `lambda_(p)` respectively. The ratio `(lambda_(p))/(lambda_(alpha))` is :

Text Solution

Verified by Experts

The correct Answer is:
3
` :. lambda = h/p = h/(sqrt(2qVm))`
or `lambda prop 1/(sqrt(qm))`
`(lambda_(p))/(lambda_(alpha))=sqrt((q_(alpha))/(q_(p)).(m_(alpha))/(m_(p)))`
`=sqrt(((2)(4))/((1)(1)))approx 2.83 `
The nearest integer is 3
Promotional Banner

Similar Questions

Explore conceptually related problems

An a- particle and a proton are accelerated from rest by a potential difference of 100 V After this their de Broglie wavelength are lambda_(a) and lambda_(p) respectively The ratio (lambda_(p))/ lambda_(p)) , to the rearest integer is

An a- particle and a proton are accelerated from rest by a potential difference of 100V. After this, their de-Broglie wavelengths are lambda_a and lambda_p respectively. The ratio (lambda_p)/(lambda_a) , to the nearest integer, is.

de-Broglie wavelength lambda is

An alpha -particle and a proton are accelerated from rest through the same potential difference V. Find the ratio of de-Broglie wavelength associated with them.

The de Broglie wavelength lambda of a particle

A proton and an alpha -particle are accelerated, using the same potential difference. How are the de-Broglie wavelengths lambda_(p) and lambda_(a) related to each other?

An alpha-"particle" is accelerated through a potential difference of V volts from rest. The de-Broglie's wavelengths associated with it is.