Home
Class 12
PHYSICS
In an electron microscope, the resolutio...

In an electron microscope, the resolution that can be achieved is of the order of the wavelength of electrons used. To resolve a width of `7.5 xx 10^(-12)` m, the minimum electron energy required is close to :

A

500 KeV

B

25 KeV

C

1 KeV

D

100 KeV

Text Solution

Verified by Experts

The correct Answer is:
B

`lambda(Å) =sqrt((150)/V)rArr7.5 xx10^(-2)=sqrt((150)/V)`
`V=150/(7.5xx7.5xx10^(-4))=80/3 KeV`
Nearby value is 25 KeV .
Promotional Banner

Similar Questions

Explore conceptually related problems

In an electron microscope, the resolution that can be achieved is of the order of the wavelength of electrons used. To resolve a width of 17.5 xx 10^(-12) m, the minimum electron energy required is close to:

The wavelength of an electron of energy 10 keV will be :

The minimum energy required to remove an electron is called

We wish to see inside an atom. Assuming the atom to have a diameter of 100 pm , this means that one must be able to resolve a width of say 10 pm . If an electron microscope is used, the minimum electron energy required is about

What will be de Broglie's wavelength of an electron moving with a velocity of 1.2 xx 10^(5) ms^(-1) ?

The circumference of second orbit of hydrogen atom, if the wavelength of electron is 5 xx 10^(-9)m will be

The de Broglie wavelength of an electron (m=9.11 xx 10^(-31) kg) is 1.2 xx 10^(-10)m . Determine the kinetic energy of the electron.

In an electron mircroscope, electrons are accelerated to great velocities. Calculate the wavelength of an electron travelling with a velocity of 7.0 megameters per second. The mass of an electron is 9.1 xx 10^-28 g .

Assertion: An electron microscop can achieve better resolving power then an optical microscope. Reason : The de-broglie wavelength of the electrons emitted form an electron gun with velocity 500m//s is much less than 500nm .