A particle A of mass ‘m’ and charge ‘q’ ...

A particle A of mass ‘m’ and charge ‘q’ is accelerated by a potential difference of 50 V. Another particle B of mass ‘4 m’ and charge ‘q’ is accelerated by a potential difference of 2500 V. The ratio of de-Broglie wavelengths `(lambda_A)/(lambda_B)` is close to :

A

`14.14`

B

`10.00`

C

`0.07`

D

`4.47`

Verified by Experts

The correct Answer is:

A

`lambda =h/(sqrt(2mqV))`
`(lambda_(p))/(lambda_(a))=sqrt((4xx1xx2500)/(1xx1xx50))=10sqrt(2)=14.14`

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