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In a historical experiment to determine Planck's constant, a metal surface was irradiated with light of different wavelengths. The emitted photoelectron energies were measured by applying a stopping potential. The relevant data for the wavelength `(lambda)`. ) of incident light and the corresponding stopping potential `(V_0 )` are given below :

Given that `c=3xx10^8ms^(-1) and e=1.6xx10^(-19)C` Planck's constant (in units of J s) found from such an experiment is

A

`6.0 xx 10^(-34)`

B

`6.4 xx 10^(-34)`

C

`6.6 xx 10^(-34)`

D

`6.8 xx 10^(-34)`

Text Solution

Verified by Experts

The correct Answer is:
B
`K_("max") =(hc)/lambda -phi_(0)rArreV = (hc)/lambda -phi`
`rArr e(V_(1)-V_(2))=(hc)/(lambda_(1))-(hc)/(lambda_(2))`
`rArr h = (e(V_(1)-V_(2))lambda_(1)lambda_(2))/(c(lambda_(2)-lambda_(1)))`
`=(1.6 xx 10^(-19)xx1xx0.3 xx0.4 xx 10^(-6)xx10^(-6))/(3xx10^(8)xx0.1xx10^(-6))`
`= 6.4 xx 10^(-34)`
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