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The magnetic field associated with a lig...

The magnetic field associated with a light wave is given, at the origin, by
`B=B_(0)[sin(3.14xx10^(7))ct +sin(6.28xx10^(7))ct].`
If this light falls on a silver plate having a work function fo 4.7 eV, what will be the maximum kinetic energy of the photo electrons?
`(c=3xx10^(8)ms^(-1),h=6.6xx10^(-34)J-s)`

A

6.82 eV

B

12.5 eV

C

7.72 eV

D

8.52 eV

Text Solution

Verified by Experts

The correct Answer is:
C
`B=B_(0) [sin (3.14 xx10^(7))ct +sin (6.28 xx 10^(7))ct] `
`omega = 2pi xx 10^(7) xx 3 xx 10^(8) = 2pi f `
`lambda = c/f = 1000 Å`
`E = (12400)/(1000) eV = 12.4 eV `
`K_("max") = E - phi =12.4 -4.7 = 7.7 eV `
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