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The stopping potential V(0) (in volt) a...

The stopping potential `V_(0)` (in volt) as a function of frequency (v) for a sodium emitter, is shown in the figure. The work function of sodium, from the data plotted in the figure, will be:
(Given : Planck’s constant)
`(h) = 6.63 xx10^(-34)Js" electron charge "e=1.6xx10^(-19)C`)

A

1.95 eV

B

1.66 eV

C

2.12 eV

D

1.82 eV

Text Solution

Verified by Experts

The correct Answer is:
B
Using above diagram
`v_(th)= 4 xx 10^(14) Hz`
`W = (hv_(th))/e " in "eV `
`W = (6.63 xx10^(-34)xx4xx10^(14))/(1.6 xx 10^(-19))=1.66 eV`
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