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The potential difference applied to an X...

The potential difference applied to an X - ray tube is 5 kV and the current through it is 3.2 . Then the number of electrons striking the target per second is

A

`2xx10^(16)`

B

`5xx10^(16)`

C

`1 xx 10^(17)`

D

`4 xx 10^(15)`

Text Solution

Verified by Experts

The correct Answer is:
A
`i = ("n e")/t rArrn/t =i/e = (3.2 xx 10^(-3))/(1.6 xx 10^(-19))= 2xx10^(16)`
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