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The K(alpha) X-ray emission line of tung...

The `K_(alpha) X`-ray emission line of tungsten occurs at `lambda = 0.021 nm`. The energy difference between K and L levels in this aotm is about : `0.51 MeV`

A

0.51 MeV

B

1.2 MeV

C

59 KeV

D

13.6 eV

Text Solution

Verified by Experts

The correct Answer is:
C
`E_(K)-E_(L) = (hc)/lambda =(6.6 xx 10^(-34)xx3xx10^(8))/((0.021 xx 10^(-9))(1.6 xx 10^(-19)))eV`
`approx ` 59 K eV.
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