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Kalpha wavelength emitted by an atom of ...

`K_alpha` wavelength emitted by an atom of atomic number Z=11 is `lambda`. Find the atomic number for an atom that emits `K_alpha` radiation with wavelength `4lambda`.
(a) Z=6 (b) Z=4
(c ) Z=11 (d) Z=44.

A

Z=6

B

Z=4

C

Z=11

D

Z=44

Text Solution

Verified by Experts

The correct Answer is:
A
`f = a^(2) (Z-1)^(2)=1/lambda `
`rArr (lambda_(2))/(f_(2))=(f_(1))/(f_(2)) = ((11-1)^(2))/((Z_(2)-1)^(2)) rArrsqrt(4/1)=10/(Z-1) rArr Z = 6`
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