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If a semiconductor photodiode can detec...

If a semiconductor photodiode can detect a photon with a maximum wavelength of 400 nm, then its band gap energy is : Planck's constant `h= 6.63 xx 10^(-34) J.s`
Speed of light `c= 3xx10^8 m//s`

A

1.1 eV

B

2.0 eV

C

1.5 eV

D

3.1 eV

Text Solution

Verified by Experts

The correct Answer is:
D
`lambda = 400` nm
Band gap `E_(g) = (hc)/lambda =(1237.5)/400=3.09 eV `
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