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When an electron in hydrogen atom is exc...

When an electron in hydrogen atom is excited, from its `4`th to `5`the stationary orbit, the change in angular momentum of electron is (Planck's constant: `h = 6.6 xx 10^(-34) J-s`)

A

`4.16 xx 10^(-34) J-s`

B

`3.32 xx 10^(-34) J-s`

C

`1.05 xx 10^(-34)J-s`

D

`2.08 xx 10^(-34) J-s`

Text Solution

Verified by Experts

The correct Answer is:
C
Change in the angular momentum
`Delta L= L_(2)- L_(1) = (n_(2)h)/(2pi) - (n_(1)h)/(2pi)`
`Delta Delta L= (h)/(2pi) [n_(2)-n_(1)] = (6.6 xx 10^(-34))/(2 xx 3.14) xx (5-4)`
`=1.05 xx 10^(-34J` -sec
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