The radius of the first (lowest) orbit o...

The radius of the first (lowest) orbit of the hydrogen atom is `a_(0)`. The radius of the second (next higher) orbit will be

A

`4a_(0)`

B

`6a_(0)`

C

`8a_(0)`

D

`10a_(0)`

Verified by Experts

The correct Answer is:

A

Since, `r_(n) prop n^(2) rArr r_(n)= r_(0)n^(2)`
`rArr r_(2)= 4r_(0)= 4a_(0) [r_(0)= a_(0)]`

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