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In the nth orbit, the energy of an elect...

In the nth orbit, the energy of an electron `E_(n)= -( 13.6)/(n^(2)) eV` for hydrogen atom. The energy required to take the electron from first orbit to second orbit will be

A

10.2 eV

B

12.1 eV

C

13.6 eV

D

3.4 eV

Text Solution

Verified by Experts

The correct Answer is:
A

Since, `E_(n)= (-13.6)/(n^(2)) eV`
`E_(2)= (-13.6)/((2)^(2))= -3.4eV`
Now, `E_(2)- E_(1)= -3.4 - (-13.6) = 10.2eV`
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