The ionisation energy of hydrogen atom i...

The ionisation energy of hydrogen atom is `13.6 eV`. Following Bohr's theory, the energy corresponding to a transition between the `3`rd and the `4`th orbit is

A

3.40 eV

B

1.51 eV

C

0.85 eV

D

0.66eV

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The correct Answer is:

D

`E_(n)= (-13.6)/(n^(2))`
`E_(3)= (-13.6)/(9) = - 1.51eV and E_(4)= (-13.6)/(16)= - 0.85eV`
`therefore E_(4)- E_(3)= 0.66eV`

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