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The ratio of the largest to shortest wav...

The ratio of the largest to shortest wavelength in Lyman series of hydrogen spectra is

A

`(25)/(9)`

B

`(17)/(6)`

C

`(9)/(5)`

D

`(4)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
For longest wavelength `(n_(1) = 1, n_(2)=2)`
`(1)/(lamda_("max"))= R [(1)/(1)- (1)/(2^(2))]= (3R)/(4)`
For shortest wavelength `(n_(1)=1, n_(2) = oo)`
`(1)/(lamda_("min")) = R[1- 0]= R rArr (lamda_("max"))/(lamda_("min"))= (4)/(3)`
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