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For Balmer series, wavelength of first l...

For Balmer series, wavelength of first line is `lamda_(1)` and for Brackett series, wavelength of first line is `lamda_(2)` then `(lamda_(1))/(lamda_(2))`

A

`0.081`

B

`0.162`

C

`0.198`

D

`0.238`

Text Solution

Verified by Experts

The correct Answer is:
B
For Balmer series `(1)/(lamda_(1))= R ((1)/(2^(2))- (1)/(3^(2)))= (5R)/(36)`
For Brackett series
`(1)/(lamda_(2))= R ((1)/(4^(2))- (1)/(5^(2))) = (9R)/(16 xx 25)`
`(lamda_(1))/(lamda_(2))= (9R)/(16 xx 25) xx (36)/(5R) = 0.162`
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