Home
Class 12
PHYSICS
Two energy levels of an electron in an a...

Two energy levels of an electron in an atom are separated by 2.3 eV. The frequency of radiation emitted when the electrons go from higher to lower level is

A

`6.95 xx 10^(14)Hz`

B

`3.68 xx 10^(15) Hz`

C

`5.6 xx 10^(14)Hz`

D

`9.11 xx 10^(15)Hz`

Text Solution

Verified by Experts

The correct Answer is:
C

`Delta E= h f`
`rArr f= (2.3 xx 1.6 xx 10^(-19))/(6.6 xx 10^(-34)) = 5.6 xx 10^(14) Hz`
Promotional Banner

Similar Questions

Explore conceptually related problems

The frequency of radiations , emitted when the electron falls , from n=4 to n=1 in a hydrogen , atom

A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom transits form the upper level to the lower level.

Calculate the energy and frequency of the radiation emitted when an electron jumps from n=3 to n=2 ina hydrogen atom.

The wavelength of radiation emitted due to transition of electron from energy level E to zero is equal to lamda . The wavelength of radiation (lamda_(1)) emitted when electronjumpsfrom energy level (3E)/(2) to zero will be :

In a hydrogen atom, ultraviolet radiations are emitted when the electron jumps from

The maximum number of photons emitted when an electron jumps from an energy level n=4 to n=1 is

The maximum number of photons emitted when an electron jumps from an energy level n=5 to n=1 is s