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When .92 U^235 undergoes fission, 0.1 % ...

When `._92 U^235` undergoes fission, `0.1 %` of its original mass is changed into energy. How much energy is released if `1 kg` of `._92 U^235` undergoes fission ?

A

`9xx 10^(10)J`

B

`9 xx 10^(11)J`

C

`9xx 10^(12)J`

D

`9 xx 10^(13)J`

Text Solution

Verified by Experts

The correct Answer is:
D
`Delta m`= mass defect `=1 xx (0.1)/(100) = 10^(-3) kg`
`therefore E= Delta mc^(2) = 10^(-3) xx (3 xx 10^(8))^(2) = 9 xx 10^(13) J`
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