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U^238 decays into Th^234 by the emission...

`U^238` decays into `Th^234` by the emission of an a-particle. There follows a chain of further radioactive decays, either by `alpha`-decay or by `beta-`decay. Eventually a stable nuclide is reached and after that, no further radioactive decay is possible. which of the following stable nuclides is the end product of the `U^238` radioactive decay chain ?

A

`Pb^(206)`

B

`Pb^(207)`

C

`Pb^(208)`

D

`Pb^(209)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(4n+2)` series starts from `U^(238)` and it.s stable end product is `Pb^(206)`
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