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The neutron separation energy is defined...

The neutron separation energy is defined to be the energy required to remove a neutron form nucleus. Obtain the neutron separation energy of the nuclei `._(20)Ca^(41)` and `._(13)Al^(27)` from the following data : `m(._20Ca^(40))=39.962591u` and `m(._(20)Ca^(41))=40.962278u`
`m(._(13)Al^(26))=25.986895u` and `m(._(13)Al^(27))=26.981541u`

A

7.57 MeV

B

8.36 MeV

C

9.12 MeV

D

9.56 MeV

Text Solution

Verified by Experts

The correct Answer is:
B
`""_(20)^(41)Ca rarr ""_(20)^(40)Ca + ""_(0)^(1) n`
Mass defect `(Delta m) = [m (""_(20)^(40)Ca) + m_(n)- m (""_(20)^(41) Ca)]` = 0.008963u
`therefore` Neutron separation energy `= 0.008963 xx 931.5 MeV`
`~~ 8.36 MeV`
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