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In a nuclear fusion reaction, two nuclei...

In a nuclear fusion reaction, two nuclei, A & B , fuse to produce a nucleus C , releasing an amount of energy `DeltaE` in the process. If the mass defects of the three nuclei are `DeltaM_A, DeltaM_B` & `DeltaM_C` respectively , then which of the following relations holds ? Here, c is the speed of light.

A

`Delta M_(A) + Delta M_(B)= Delta M_(C) - Delta E//c^(2)`

B

`Delta M_(A) + Delta M_(B)= Delta M_(C) + Delta E//c^(2)`

C

`Delta M_(A)- Delta M_(B)= Delta M_(C) + Delta E//c^(2)`

D

`Delta M_(A) - Delta M_(B)= Delta M_(C) + Delta E//c^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`A + B rarr C`
Energy released
`= ((E_(b))_(C)- [(E_(b))_(A) + (E_(b))_(B)]`
`= Delta M_(C) (c^(2)) - (Delta M_(A) + Delta M_(B))_(C^(2))`
`therefore Delta M_(A) + Delta M_(B)= Delta M_(C)- (Delta E)/(c^(2))`
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