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The gravitational force between a H-atom...

The gravitational force between a H-atom and another particle of mass m will be given by Newton's law: `F=G (M.m)/(r^(2)`, where r is in km and

A

`M = m_("proton") + m_("electron")`

B

`M= m_("proton") + m_("electron") - (B)/(c^(2) (B= 13.6eV)`

C

M is not relate to the mass of the hydrogen atom

D

`M= m_("proton") + m_("electron") - (|V|)/(c^(2))` (`|V|`= magnitude of the potential energy of electron in the H-atom)

Text Solution

Verified by Experts

The correct Answer is:
B
Given `F= (GM m)/(r^(2))`
M = Effective mass of hydrogen atom
= Mass of electron + Mass of proton `- (B)/(c^(2))` where B is BE of hydrogen atom = 13 6. eV
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