If the nuclear radius of .^27 A1 is 3.6 ...

If the nuclear radius of `.^27 A1` is `3.6` Fermi, the approximate nuclear radius of `64 Cu` in Fermi is :

A

2.4

B

1.2

C

4.8

D

3.6

Verified by Experts

The correct Answer is:

C

`R= R_(0) A^((1)/(3)) rArr R prop A^((1)/(3))`
`(R_(Al))/(R_(Cu)) = ((27)/(64))^((1)/(3)) = (3)/(4) rArr R_(Cu) = (4)/(3) xx 3.6 = 4.8`

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