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Order of magnitude of density of uranium...

Order of magnitude of density of uranium nucleus is , [m = 1.67 xx 10^(-27 kg]`

A

`10^(20) kg//m^(3)`

B

`10^(17) kg//m^(3)`

C

`10^(14) kg//m^(3)`

D

`10^(11) kg//m^(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
`m= A xx 1.67 xx 10^(-27) kg`
Volume `= (4)/(3) pi R^(3) = (4)/(3) pi [(1.25 xx 10^(-15))A^(1//3)]^(3) ~~ *8.2 xx 10^(-45) m^(3))A`
`therefore` (Density `(rho) = (m)/(V) = (1.67 xx 10^(-27))/(8.2 xx 10^(-45)) = 2 xx 10^(17) kg //m^(3)`
Note : Density is independent of mass number.
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