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The ratio of half-life times of two elem...

The ratio of half-life times of two elements `A` and `B` is `(T_(A))/(T_(B))`. The ratio of respective decay constant `(lambda_(A))/(lambda_(B))`,is

A

`T_(B)//T_(A)`

B

`T_(A)//T_(B)`

C

`(T_(A)- T_(B))/(T_(A))`

D

`(T_(A)- T_(B))/(T_(A))`

Text Solution

Verified by Experts

The correct Answer is:
A

`T_(1//2)= (ln 2)/(lamda)`
`therefore (T_(A))/(T_(B)) = (lamda_(B))/(lamda_(A)) rArr (lamda_(A))/(lamda_(B))= (T_(B))/(T_(A))`
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