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A radio-isotope has a half-life of 5 yea...

A radio-isotope has a half-life of `5` yeard. The fraction of the atoms of this material that would decay in `15` years will be

A

`1//8`

B

`2//3`

C

`7//8`

D

`5//8`

Text Solution

Verified by Experts

The correct Answer is:
C
Number of nuclei remaining `= (N_(0))/(2^(n)) = (N_(0))/(2^(3)) = (N_(0))/(8) [n = (15)/(5)= 3]`
Decayed fraction `= 1 - (1)/(8)= (7)/(8)`
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