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Radon (Ra) decays into Polonium (P0) by ...

Radon `(Ra)` decays into Polonium `(P_0)` by emitting an `alpha-`particle with half-life of `4` days. A sample contains `6.4 xx 10^10` atoms of `R_n`. After `12` days, the number of atoms of `R_n` left in the sample will be

A

`3.2 xx 10^(10)`

B

`0.53 xx 10^(10)`

C

`2.1 xx 10^(10)`

D

`0.8 xx 10^(10)`

Text Solution

Verified by Experts

The correct Answer is:
D
12 days `= 3T_(1//2)`
Number of nuclei remaining
`= (N_(0))/(2^(n)) = (6.4 xx 10^(10))/(2^(3))= 0.8 xx 10^(10)`
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