During mean life of a radioactive elemen...

During mean life of a radioactive element, the fraction that disintegrates is

A

e

B

`(1)/(e)`

C

`(e-1)/(e)`

D

`(e)/(e-1)`

Verified by Experts

The correct Answer is:

C

`N= N_(0)e^(- lamda t) rArr N = (N_(0))/(e) (" at " t= tau = (1)/(lamda))`
Disintegrated fraction `=1 - (N)/(N_(0))= 1- (1)/(e)= (e- 1)/(e)`

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