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If .92 U^238 undergoes successively 8 al...

If `._92 U^238` undergoes successively `8 alpha-`decays and `6 beta-`decays, then resulting nucleus is.

A

`""_(82)U^(206)`

B

`""_(82)Pb^(206)`

C

`""_(82)U^(210)`

D

`""_(82)U^(214)`

Text Solution

Verified by Experts

The correct Answer is:
B
`A= 238 - 8 xx 4= 206`
`Z= 92- 8 xx 2+ 6= 82`
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