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A radioactive decay chain starts from .9...

A radioactive decay chain starts from `._93 Np^237` and produces `._90 Th^229` by successive emissions. The emitted particles can be

A

Two `alpha`-particles and one `beta`-particle

B

Three `beta^(+)` particles

C

One `alpha` particle and two `beta^(+)` particles

D

One `alpha` particle and two `beta^(-)` particles

Text Solution

Verified by Experts

The correct Answer is:
A
Number of `alpha`- particle `(n_(alpha))= (A- A.)/(4)= (237 - 229)/(4)= 2`
Number of `beta`- particle `(n_(beta))= 2n_(alpha)- Z + Z.`
`=2 xx 2- 93 + 90=1`
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