What is the respective number of alpha a...

What is the respective number of `alpha` and `beta` particles emitted in the following radioactive decay? `._(90)X^(200) rarr ._(80)Y^(168)`

A

6 and 8

B

8 and 8

C

6 and 6

D

8 and 6

Verified by Experts

The correct Answer is:

D

`n_(alpha)= (A- A.)/(4)= (200- 168)/(4)= 8`
`n_(beta) = 2n_(alpha)- Z + Z.= 2 xx 8 - 90 + 80= 6`

Similar Questions

Explore conceptually related problems

What are the respective number of alpha and beta -particles emitted in the following radioactive decay?

What are the respective number of alpha - and beta - particle emitted in the following radioactive decay ? ""_(90)^(200)X to ""_(80)^(168)Y

Find out the total number of alpha and beta- particles in the following disintegration: ._(90)Th^(228) rarr ._(83)Bi^(212)

The number of alpha and beta -particles emitted in the nuclear reaction ._(90)^(210) Th to ._(83)^(212)Bi are:

Calculate the number of alpha - and beta -particles emitted when ._(92)U^(238) into radioactive ._(82)Pb^(206) .