Consider a nuclear reaction `A+B rarr C`. A nucleus `A` moving with kinetic energy of `5 MeV` collides with a nucleus `B` moving with kinetic energy of `3MeV` and forms a nucleus `C` in excited state. Find the kinetic energy of nucleus `C` just after its formation if it is formed in a state with excitation energy `10 MeV`. Take masses of nuclei of `A,B` and `C ` as `25.0,10.0,34.995 amu`, respectively.
`(1amu=930 MeV//c^(2))`.

Answer

3

Explanation

Applying conservation of energy
`m_(A)c^(2)+K_(A)+m_(B)c^(2)+K_(B)=m_(c)c^(2)+K_(c )+ "excitation energy "`
`(m_(A)+m_(B)-m_(c ))c^(2)+K_(A)+K_(B)=K_(C )+" excitation energy "`
`4.65 +5 + 3.35 =K_(c )+10`
or `K_(c )=3 ` MeV.