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As par Bohr model, the minimum energy (i...

As par Bohr model, the minimum energy (in `eV`) required to remove an electron from the ground state of doubly ionized `Li` atom `(Z = 3)` is

A

`1.51`

B

`13.6`

C

`40.8`

D

`122.4`

Text Solution

Verified by Experts

The correct Answer is:
D
`E = -13.6 ((Z^(2))/(n^(2)))eV `
`= - 13.6 ((3)^(2))/(1^(2)) = - 122.4 eV `
Hence , ionisation energy = 122.4 eV
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