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An energy of 24.6 eV is required to remo...

An energy of `24.6 eV` is required to remove one of that electrons from a neutal helium atom. The enegy (in `eV`)required to remove both the electrons from a netural helium atom is

A

`79.0`

B

`51.8`

C

`49.2`

D

`38.2`

Text Solution

Verified by Experts

The correct Answer is:
A
(For `2^(nd)`electron) = `(13.6 xx(2)^(2))/1= 54.4 eV`
Ionization energy (E ) = `(13.6Z^(2))/(n^(2))`
Total energy = `54.4 +24.6 = 79 eV `.
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