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If lambda(Cu) is the wavelength of K(alp...

If `lambda_(Cu)` is the wavelength of `K_(alpha)` X-ray line of copper (atomic number `29`) and `lambda_(Mo)` is the wavelength of the `K_(alpha)`X-ray line of molybdenum (atomic number `42`),then the ratio `lambda_(Cu)//lambda_(Mo)` is close to

A

`1.99`

B

`2.14`

C

`0.50`

D

`0.48`

Text Solution

Verified by Experts

The correct Answer is:
B
`lambda prop 1/((Z-1)^(2))`
`rArr (lambda_(Cu))/(lambda_(Mo)) =((Z_(Mo)-1)^(2))/((Z_(Cu)-1)^(2)) =(41^(2))/(28^(2)) rArr (lambda_(Cu))/(lambda_(Mo)) = 2.144 `
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