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A hydrogen atom initially in the ground ...

A hydrogen atom initially in the ground state is excited by absorbing a photon of wavelenght 980 Å.The redius of the atom in the excited state ,in terms of Bohr radius `a_(0)` will be : `(hc= 12500 eV- Å)`

A

`16a_(0)`

B

`25a_(0)`

C

`9a_(0)`

D

`4a_(0)`

Text Solution

Verified by Experts

The correct Answer is:
A
Energy of radiation = `(12500)/980 = 12.75 eV `
Energy of electron in `n^(th)` orbit = `-(13.6)/(n^(2))`
` rArr E_(n) - E_(1) = - 13.6 [1/(n^(2))-1/1^(2)]`
`rArr 12.75 = 13.6 [1/(1^(2))-1/(1^(2))]rArr napprox 4`
Electron will transit to n = 4
New radius will be `16a_(0)` .
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