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If He^(+) ion is in its first excited st...

If `He^(+)` ion is in its first excited state then its ionization energy is

A

`13.60 `eV

B

`54.40`eV

C

`48.36`eV

D

`6.04`eV

Text Solution

Verified by Experts

The correct Answer is:
A
`E_(n) = - 13.6 (z^(2))/(n^(2))`
in first excited state for `He^(+)`
n = 2 ,z =2
`E = -13.6 xx((2)^(2))/((2)^(2))=-13.6 " eV "`
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