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Assume that a neutron breaks into a prot...

Assume that a neutron breaks into a proton and an electron. The energy released during this process is (mass of neutron = `1.6725 xx 10^(-27)` kg, mass of proton = `1.6725 xx 10^(-27) kg`, mass of electron `= 9 xx 10^(-31) kg)`

A

`0.73` MeV

B

`7.10` MeV

C

`6.30`MeV

D

`0.52`MeV

Text Solution

Verified by Experts

The correct Answer is:
D
`n to p+ bar(e ) +bar (v) +Q`
Energy released
`=[(m_(p)+m_(e )-m_(n))xx931.5] MeV `
`= [-1.6725 xx 10^(-27) +1.6725 xx10^(-27) +9xx10^(-31)] xx 931.5`
`= 9 xx 10^(-31) xx931.5 = 0.523 MeV .`
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