If radius of the .(13)^(27)Al nucleus is...

If radius of the `._(13)^(27)Al` nucleus is estimated to be `3.6` Fermi, then the radius of `._(52)^(125)Te` nucleus be nerarly:

A

4 Fermi

B

5 Fermi

C

6 Fermi

D

8 Fermi

Verified by Experts

The correct Answer is:

C

`R=R_(0)A^(1//3)rArr(R_(1))/(R_(2))=((A_(1))/(A_(2)))^(1/3)`
`rArr (3.6)/(R_(2)) =(27/125)^(1/3) =3/5 rArr R_(2) = 3.6 xx 5/3 = 6` fermi .

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