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The electrostatic energy of Z protons un...

The electrostatic energy of `Z` protons uniformly distributed throughout a spherical nucleus of radius `R` is given by
`E = (3 Z(Z- 1)e^(2))/5( 4 pi e _(0)R)`
The measured masses of the neutron `_(1)^(1) H, _(7)^(15) N and , _(8)^(16)O are 1.008665 u, 1.007825 u , 15.000109 u and 15.003065 u, ` respectively Given that the ratio of both the `_(7)^(12) N` and `_(8)^(15) O` nucleus are same , 1 u = = 931.5 Me V`c^(2) ` (c is the speed of light ) and `e^(2)//(4 pi e_(0)) = 1.44 MeV` fm Assuming that the difference between the binding energies of `_7^(15) N and `_(8)^(15) O ` is purely due to the electric energy , The radius of the nucleus of the nuclei is

A

2.85 fm

B

3.03 fm

C

3.42 fm

D

3.80 fm

Text Solution

Verified by Experts

The correct Answer is:
C

Electrosta tic energy = `BE_(N) -BE_(O)`
= `[ 7M_(p) +8M_(n) -M_(N)]-[8M_(p)+7M_(n) -M_(O)]c^(2)`
`=[-M_(p)+M_(n)+M_(O) -M_(N)]c^(2)`
`=[-1.007825 +1.008665 +15.003065 - 15.000109]`
` xx 931 .5` MeV
= `3.5359` MeV
`DeltaE = 3/5 xx(1.44 xx 8xx7)/R -3/5 xx(1.44 xx 7 xx 6)/R = 3.5359`
` rArr R = 3.42 ` fm .
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