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If N(0) is the original mass of the subs...

If `N_(0)` is the original mass of the substance of half - life period `t_(1//2) = 5 year` then the amount of substance left after `15` year is

A

`N_(0)//8`

B

`N_(0)//16`

C

`N_(0)//2`

D

`N_(0)//4`

Text Solution

Verified by Experts

The correct Answer is:
A
No . Of half life `(n) = 15/5 =3`
Amount of substance left = `(N_(0))/(2^(n)) rArr (N_(0))/(2^(3)) =(N_(0))/8`
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