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A radioactive nucleus (initial mass numb...

A radioactive nucleus (initial mass number A and atomic number Z) emits `3alpha`-particles and 2 positrons. The ratio of number of neutrons to that of protons in the final nucleus will be

A

`(A-Z-4)/(Z-2)`

B

`(A-Z-8)/(Z-4)`

C

`(A-Z-4)/(Z-8)`

D

`(A-Z-12)/(Z-4)`

Text Solution

Verified by Experts

The correct Answer is:
C
`3alpha - `decay
A = `Z-6 , A = A-12 `
2 Position `(beta^(+) - " decay ")`
`Z" = Z - 6 - 2 = Z-8`
A" = A = `A-12 `
`("Number of neutrons ")/(" Number of protons ") = (A-12-(Z-8))/(Z-8) = (A-Z-4)/(Z-8)`
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