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A nucleus with Z =92 emits the following...

A nucleus with Z =92 emits the following in a sequence:
`alpha,beta^(-),beta^(-),alpha,alpha,alpha,alpha,alpha,beta^(-),beta^(-),alpha,beta^(+),beta^(+),alpha`. The Z of the resulting nucleus is

A

74

B

76

C

78

D

82

Text Solution

Verified by Experts

The correct Answer is:
C
`8 alpha - ` decay , `4 beta ` - decay and `2beta^(+)` decay
`Z = 92 - 8 xx 2 + 4 xx 1 - 2 xx 1 = 78` .
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