Home
Class 12
PHYSICS
Using a nuclear counter the count rate o...

Using a nuclear counter the count rate of emitted particles from a radioactive source is measured. At t=0 it was 1600 counts per second and t = 8 seconds it was 100 counts per second. The count rate observed, as counts per seconds, at t=6, seconds is close to :

A

150

B

400

C

360

D

200

Text Solution

Verified by Experts

The correct Answer is:
D
`(1600)/((2)^(n)) =100`
`2^(n) = 16 rArr n = 4 `
`4 t_(1//2) = 8 s rArr t_(1//2) = 2s`
t = 6 sec { 3 half -life }
`rArr 1600/(2^(3)) = 200` .
Promotional Banner

Similar Questions

Explore conceptually related problems

Using a nuclear counter the count rate of emitted particles from a radioactive source is measured. At t = 0 seconds it was 25600 counts per second and t = 8 seconds it was 100 counts per second. The count rate observed, as counts per second, at t = 6 seconds is close to:

The counting rate observed from a radioactive source at t=0 second was 1600 counts per second and at t=8 seconds it was 100 counts per second. The counting rate observed, as counts per second at t=6 seconds, willbe

The initial count rate for a radioactive source was found to be 1600 count/sec.and t = 8 sec this rate was 100 count/sec. What was the count rate at t = 6 [in counts/sec]-

The count rate observed from a radioactive source at t second was N_0 and at 4t second it was (N_0)/(16) . The count rate observed at (11/2)t second will be

The activity of a radioactive sample is measured as 9750 counts per minute at t = 0 and as 975 counts per minute at t = 5 minutes. The decay constant is approximately

38 The activity of a radioactive substance is found to be 2400 counts per second.After one minute the material shows "300" counts per second what is its half period?

A counter gives a count of 320 counts/minute for a radioactive source . After 75 minutes, the counter shows a count rate of 40 counts/minute . What is the half life period of the source ?

The radioactivity of a substance is measured in terms of disintegration per second. Then 3 xx 10^8 dps (disintegration per second) is equal to

An electron is revolving n times per second. The charge passing in t second is