Home
Class 12
PHYSICS
In a radioactive decay chain, the initia...

In a radioactive decay chain, the initial nucleus is `overset(232)(90).^(Th)`. At the end there are 6 `alpha`-particles and 4 `beta`-particles which are emitted. If the end nucleus is `overset(A)(Z).^(X),A` and Z are given by :

A

A= 202 , Z = 80

B

A = 208 , Z = 80

C

A = 200 ,Z=81

D

A = 208 ,Z=82

Text Solution

Verified by Experts

The correct Answer is:
D

Change in `Z = (6xx2) - 4 = 8`
Change in `A = 6 xx 4 = 24`
`._(90)^(232)TH overset (6alpha) underset (4beta^(-))to ._(82)^(208) P_(B)`.
Promotional Banner

Similar Questions

Explore conceptually related problems

A nucleus ._n^ m X emits one alpha- particle and two beta- particles. The resulting nucleus is

._(92)U^(238) emits 8 alpha- particles and 6 beta- particles. The n//p ratio in the product nucleus is

A nucleus ._(Z)X^(A) emits 2 alpha - particles and 3 beta - particles. The ratio of total protons and neutrons in the final nucleus is :

How many alpha and beta -particles are emitted when uranium nucleus (._(92)U^(238)) decay to ._(82)Pb^(214) ?

A uranium nucleus ._(92)U^(238) emits and alpha -particle and a beta -particle in succession. The atomic number and mass number of the final nucleus will be

Radioactive nuclei emit beta^-1 particles. Electrons exist inside the nucleus.

How may alpha- and beta- particles will be emitted when ._(90)Th^(232) changes into ._(82)Pb^(208) ?